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(2)=5F^2-3F+6
We move all terms to the left:
(2)-(5F^2-3F+6)=0
We get rid of parentheses
-5F^2+3F-6+2=0
We add all the numbers together, and all the variables
-5F^2+3F-4=0
a = -5; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-5)·(-4)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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